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Consider the following situation:
above: tunnel lengh = 1km
bellow: motorcycle pilot point-of-view
Let us assume that the Earth is flat and that all points of its surface has the same gravitational acceleration.
In this situation, we construct a straight tunnel with a length of 1 km.
A pilot starts a motorcycle ride within that tunnel with LASER headlight on.
The view that the pilot will have inside the tunnel is approximately the same figure presented above.
Excluding the aerodynamic drag, no matter how fast the biker print on your machine. As this situation the Earth is flat, motorcycle and pilot will always continue with the same weight.
Imagine the "globe of death". When the pilot puts the motorcycle in motion once it reaches a certain speed, it will have the impression of the vehicle "always going up." There will be a strong pressure of the wheels of the motorcycle on the inner wall of the globe, as well as pilot pressure on the saddle will increase.
These effects are caused by centripetal force, as the motorcycle tends to go straight, but the wall of the globe under the set below a constant curve radius line.
Now imagine a tunnel involving all the equatorial circle of the earth.
Equator's tunnel segment and motocycle pilot point-of-view
In this situation, the motorcycle laser beam will hit the roof of the tunnel.
In the manner that the rider increases speed of the bike, the rider will have the feeling of being "down" because the bike will tend to follow a straight line tangent to the Earth and the floor of the tunnel toroidal surface.
If the engine speed reaches a speed of 11,000 meters per second, the motorcycle and the pilot will tend to escape the Earth's gravity.
In this situation, the pilot will have to drive the bike into the tunnel with the wheels up and his head pointing toward the center of the Earth.
So far, nothing new ...
When we build a toroidal tunnel on the Arctic circle, for example, we have an unusual situation:
When the motorcycle reaches great speed, appear two centripetal forces:
The more predictable force is the one that propels the motorcycle and pilot to remain at the same distance from the center of the toroid.
But now the Earth is round ...
In this real situation, the motorcycle and pilot are always the same distance from the center of the Earth. Bike and rider make a DOUBLY radial trajectory:
A relative to the center of the toroid, the other in relation to the center of the earth ..
The ´point-of-view of pilot in this situation will be about this:
The target of laser points where the wheels of the motorcycle will stand.
The "end of the tunnel" moves to the side and downwards. The laser beam hits the roof of the tunnel.
When the motorcycle reaches a speed of 11,000 meters per second, it will have to hike up the base of the toroid at some point on angle located between "noon" and "three hours" of an analog clock.
In other words, the motorcycle wheels will push the ceiling of the tunnel. The tunnel will have to climb.
The Fight Saucer (or ring saucer)
Build a tunnel inside the toroid.
Push a gas to circulate inside the toroid at a speed of 11,000 km / s or more.
Place the toroid on the surface of the Earth.
All points of toroid base must sit at same distance from Earth's center.
According to Newton's ballistics, the toroid will floats!
Resultant Vectors Map.
Arrow Symbol
"vai" = "go"
"vem" = "comes"
Green: head of arrow - Red: tail of arrow.
The reasoning of complete cancellation of forces is true when the toroid is on the equator.
Assume that the base diameter of the toroid is placed on the earth (like a perfect sphere) has the same diameter of the our planet.
Therefore, the sum of all reaction forces arising from the motion of the gas, AND FORCES OF ACTION GRAVITY will be null. SINCE THE EARTH IS STOP.
But if the toroid has a smaller diameter than the Earth, the resultant of forces changes.
Note that in the first example, "put" the toroid on the Arctic circle, But it does not matter.
If a toroid is "placed" in the southern hemisphere (as shown in the detail picture above), all points that toroid touching the earth will have the same distance from the center of the Earth.
By analyzing the vectors of toroid when he is on the equator, the resulting forces resulting between attraction of the earth and the tendency of the gas to escape through the tangent (erroneously known as "centrifugal force") is completely null.
However, when the diameter of toroid reduces, the vectorial composition of gravitational and centripetal forces do not cancel completely.
Check that the forces resulting from gravitational and centripetal attraction will have the following consequences:
- The resulting vector (placed at the equator) A between A' be null;
- The resulting vectors B between B' is not completely null,
- The arrays C between C' does is not completely null.
The resulting forces (B + B') OR (C + C') vectors that give rise to "compel" the toroid depart from the earth's surface. "The accelerated gas will go into orbit."
To be or not to be...
above: tunnel lengh = 1km
bellow: motorcycle pilot point-of-view
Let us assume that the Earth is flat and that all points of its surface has the same gravitational acceleration.
In this situation, we construct a straight tunnel with a length of 1 km.
A pilot starts a motorcycle ride within that tunnel with LASER headlight on.
The view that the pilot will have inside the tunnel is approximately the same figure presented above.
Excluding the aerodynamic drag, no matter how fast the biker print on your machine. As this situation the Earth is flat, motorcycle and pilot will always continue with the same weight.
Imagine the "globe of death". When the pilot puts the motorcycle in motion once it reaches a certain speed, it will have the impression of the vehicle "always going up." There will be a strong pressure of the wheels of the motorcycle on the inner wall of the globe, as well as pilot pressure on the saddle will increase.
These effects are caused by centripetal force, as the motorcycle tends to go straight, but the wall of the globe under the set below a constant curve radius line.
Now imagine a tunnel involving all the equatorial circle of the earth.
Equator's tunnel segment and motocycle pilot point-of-view
In this situation, the motorcycle laser beam will hit the roof of the tunnel.
In the manner that the rider increases speed of the bike, the rider will have the feeling of being "down" because the bike will tend to follow a straight line tangent to the Earth and the floor of the tunnel toroidal surface.
If the engine speed reaches a speed of 11,000 meters per second, the motorcycle and the pilot will tend to escape the Earth's gravity.
In this situation, the pilot will have to drive the bike into the tunnel with the wheels up and his head pointing toward the center of the Earth.
So far, nothing new ...
When we build a toroidal tunnel on the Arctic circle, for example, we have an unusual situation:
When the motorcycle reaches great speed, appear two centripetal forces:
The more predictable force is the one that propels the motorcycle and pilot to remain at the same distance from the center of the toroid.
But now the Earth is round ...
In this real situation, the motorcycle and pilot are always the same distance from the center of the Earth. Bike and rider make a DOUBLY radial trajectory:
A relative to the center of the toroid, the other in relation to the center of the earth ..
The ´point-of-view of pilot in this situation will be about this:
The target of laser points where the wheels of the motorcycle will stand.
The "end of the tunnel" moves to the side and downwards. The laser beam hits the roof of the tunnel.
When the motorcycle reaches a speed of 11,000 meters per second, it will have to hike up the base of the toroid at some point on angle located between "noon" and "three hours" of an analog clock.
In other words, the motorcycle wheels will push the ceiling of the tunnel. The tunnel will have to climb.
The Fight Saucer (or ring saucer)
Build a tunnel inside the toroid.
Push a gas to circulate inside the toroid at a speed of 11,000 km / s or more.
Place the toroid on the surface of the Earth.
All points of toroid base must sit at same distance from Earth's center.
According to Newton's ballistics, the toroid will floats!
Resultant Vectors Map.
Arrow Symbol
"vai" = "go"
"vem" = "comes"
Green: head of arrow - Red: tail of arrow.
The reasoning of complete cancellation of forces is true when the toroid is on the equator.
Assume that the base diameter of the toroid is placed on the earth (like a perfect sphere) has the same diameter of the our planet.
Therefore, the sum of all reaction forces arising from the motion of the gas, AND FORCES OF ACTION GRAVITY will be null. SINCE THE EARTH IS STOP.
But if the toroid has a smaller diameter than the Earth, the resultant of forces changes.
Note that in the first example, "put" the toroid on the Arctic circle, But it does not matter.
If a toroid is "placed" in the southern hemisphere (as shown in the detail picture above), all points that toroid touching the earth will have the same distance from the center of the Earth.
By analyzing the vectors of toroid when he is on the equator, the resulting forces resulting between attraction of the earth and the tendency of the gas to escape through the tangent (erroneously known as "centrifugal force") is completely null.
However, when the diameter of toroid reduces, the vectorial composition of gravitational and centripetal forces do not cancel completely.
Check that the forces resulting from gravitational and centripetal attraction will have the following consequences:
- The resulting vector (placed at the equator) A between A' be null;
- The resulting vectors B between B' is not completely null,
- The arrays C between C' does is not completely null.
The resulting forces (B + B') OR (C + C') vectors that give rise to "compel" the toroid depart from the earth's surface. "The accelerated gas will go into orbit."
To be or not to be...
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