It is 18Vx 2.25Amps, every second. but it does not LAST a whole second.
My SWAG (scientific wild assed guess) is that the dump lasts 1/10 or 1/8th of a second.
so that's 18x2.25Watts *0.1s. that gives you the joules it dumps (about 4):
about 4 Joules every seccond, which again averages to 4W (measurable) electric
'output' power. Scope shot would tell you exactly and by integrating the surface
below the curve (waveform) you could get a better estimate.
input is 12V*1A? looks like underunity to me....
So if you charge the battery for any amount of time for an hour (3600 s) you've dumped
3600s*4W = 14400 Joules or 4Whr into the battery.
If you can pull out more than that from the battery before it reaches it's initial charge level or
some low lever.... then you've shown that john Bedini is right and it's not the current that
charges the battery.
Anyone shown that yet?
Anything wrong in what I said?
Yves Baggi
My SWAG (scientific wild assed guess) is that the dump lasts 1/10 or 1/8th of a second.
so that's 18x2.25Watts *0.1s. that gives you the joules it dumps (about 4):
about 4 Joules every seccond, which again averages to 4W (measurable) electric
'output' power. Scope shot would tell you exactly and by integrating the surface
below the curve (waveform) you could get a better estimate.
input is 12V*1A? looks like underunity to me....
So if you charge the battery for any amount of time for an hour (3600 s) you've dumped
3600s*4W = 14400 Joules or 4Whr into the battery.
If you can pull out more than that from the battery before it reaches it's initial charge level or
some low lever.... then you've shown that john Bedini is right and it's not the current that
charges the battery.
Anyone shown that yet?
Anything wrong in what I said?
Yves Baggi
Originally posted by min2oly
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