A few newbie questions.

[kingstingtin]

Thanks Tom, for the quick reply.
New battery, I have not used (yet to be charged the old battery).
Graph I got from the manufacturer's instructions. Here it is:
How can I nevertheless do?

[Tom C]

if you look at the discharge curves at 100% depth of discharge you get 200 cycles. if you want 120 cycles you only discharge to 30 percent of its capacity or 2.16 amps out. fully charged voltage is 2.45 volts per cell. you can decide how long you want your battery to last.

Tom C

[kingstingtin]

That is, you advise me not to discharge the battery below 12.45 V, and do not charge above 14.7V?

if you want 120 cycles you only discharge to 30 percent of its capacity or 2.16 amps out.

Maybe you were referring to 1200 cycles?

[Tom C]

yes 1200 cycles... it is all about how long you want your battereis to last.

Tom C

[kingstingtin]

Clearly, thanks. Then I will stick to 50% discharge. 400 cycles I think will be enough. But in any case, I should get COP> 1?

[kingstingtin]

I think I understand. After I stopped the discharge of the battery at 12.00V, then an hour later, the voltage across it rose to 12.18V. This means that the remaining charge is approximately 45-50%. So the next time I need to stop the discharge at about 12.05V.
Tell me, Tom, am I right?

[vallentin]

...So the next time I need to stop the discharge at about 12.05V.
Tell me, Tom, am I right?

Konstantin, you should stop at 12.2V
I have 2 identical batteries retrieved from an old UPS, 12-13 years old, got them way beyond 1200 cycles and service years. They were sitting at 3 volts when I got them.
Yes, in theory, you can discharge at min. 10.5V.
But, my advice is: don't!

[kingstingtin]

As far as I understand, the level of discharge of the battery is determined by the voltage with no load.
After disconnecting the load, the battery voltage rises slightly. If I disable the load when the voltage is 12.2 V, the rate of discharge is less than 50% (ie, the battery will stay more than 50% of energy). 12.2V - about 50% of the charge. So if I want to reach 50% charge, I have to disconnect the load a little less than 12.2 V.

[kingstingtin]

I do not know how to relate to silence guru, for my questions.
John K, Tom C, can I offer you three answers?
Please choose the correct one.
1. you're so ugly write in English, that nothing is clear.
2. you write frank delirium, for which do not respond.
3. Are you okay, just keep your job and do not ask stupid questions.

[Tom C]

I do not know how to relate to silence guru, for my questions.
John K, Tom C, can I offer you three answers?
Please choose the correct one.
1. you're so ugly write in English, that nothing is clear.
2. you write frank delirium, for which do not respond.
3. Are you okay, just keep your job and do not ask stupid questions.

what vallentin said..................


#4 we have a life outside of the forums and sometimes dont log in


Tom C

[kingstingtin]

Thanks, I felt like a keener.

[kingstingtin]

Once again, hello to you all.
Since the neon lamp (NE2) is no longer cope with the protection transistor, can I use for this varistor?

[Tom C]

no you cannot. the neon has a "breakdown" voltage between 90 and 120 volts. they are on or off. I would still use the neons if I were you. transistors are expensive. they are a secondary protection, IF you are running at 12 volts. any higher you can forget it


Tom C

[kingstingtin]

Tom, please do me a discount, I badly know English and did not understand nothing.
Hell with it with varistor. What about the gas discharge tube? Such as M50-C90X?
I use a switching power supply that produces 13.6 V.
If I understand you correctly, if at the input voltage is 12V, the neon lamp helps. If voltage is greater than 12V neon lamp is does not help. I understand you correctly?

[Tom C]

Tom, please do me a discount, I badly know English and did not understand nothing.
Hell with it with varistor. What about the gas discharge tube? Such as M50-C90X?
I use a switching power supply that produces 13.6 V.
If I understand you correctly, if at the input voltage is 12V, the neon lamp helps. If voltage is greater than 12V neon lamp is does not help. I understand you correctly?

why do you want a varistor? just build it like the book says, there is not one in the circuit. the bulb is just so the machine stays in tune in the trigger as the battey charges. at 24 volts the spike gets to big for the neon to protect, unless you add resistors to it... the neon protects the gate of the transistor.

your switching power suppply may work, it may get blown up, it may get degraded. two batteries is the best way to run the SG

Tom C